(30*x^2)+(53*x)+(5)=0

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Solution for (30*x^2)+(53*x)+(5)=0 equation: 



(30x^2)+(53x)+(5)=0

a = 30; b = 53; c = +5;
Δ = b2-4ac
Δ = 532-4·30·5
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-47}{2*30}=\frac{-100}{60}
=-1+2/3
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+47}{2*30}=\frac{-6}{60}
=-1/10
$

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